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How do you take away the √ ?
You put it to the ² power
Use GEMDAS Backwards
What do you use to solve for x
what is an extraneous solution?
An apparent solution that must be rejected because it does not satisfy the original equation.
2+ square root r = 11
minus 2 on both sides= (square root r) ∧2= (9)∧2 r=81
Solve 2 + √r = 11
2 - 2 + √r = 11 - 2
Solve ³√x - 10 = -3
³√x - 10 + 10 = -3 + 10
((x - 2)∧¾)∧4/3 = 1∧4/3
Solve (x - 2)∧¾ = 1
x=4
x∧2/3 +4=12
(x+9)∧2/3=49
First: Subtract 9 from both sides
81=x²+17
First: Subtract 17 from both sides
Why do you ALWAYS check your answer?
To see if it is an extraneous solution, one that does not satisfy the original equation
Square it
How do you get rid of the square root?
Yes
Can some extraneous solutions sometimes satisfy an equation?